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Cost of FP
- Thread starter 67Sage101
- Start date
Pickleweasel
Active Member
The cost of 1 FP increases each time you buy one, so it isn't as many clicks as you might think.
Ebeondi Asi
Well-Known Member
I'm the person who bought the 600,000,000 Coins worth.. As Pickleweasel mentions the cost of each Fp goes up 50 Coins each one you buy ... forever.. So when I spent the six hundred million Coins... Each FP for me started out at 340,000 or so.. LOL
I am up to 415,000 or so per now.
I am up to 415,000 or so per now.
Pobcak1984
New Member
What did you do with all those FP's? Max out every GB?
Just curious.
Just curious.
wolfhoundtoo
Well-Known Member
At his starting cost of 314,000 that's less than 2,000 fps so no he didn't max out his GBs. Not sure what specifically they were spent on buy when I buy them I tend to use them for trades I need to pick up, sometimes to complete a GB if i was in a hurry, sometimes to give a boost to a guild mate, sometimes (back when i began playing really not so much today) to complete the invest a certain number of FPs for events. My next FP costs 979,900.
Ebeondi Asi
Well-Known Member
I used them because there is no reason for me at this time in the game, to be saving up a billion Coins. So I use them. i am constantly buying Forge Points with Coins in general. Just that World I had been busy with other stuff and in a month or so I had over seven hundred million to blow. So I used most of them, leaving a few. (a hundred million in reserve)
I do not see any point for me to have(at this time in my game) mountains of Coins. I do know I will need mountains of Coins in late Eras.. just not right now. an Coins add up fast...
Turning the Coins into useful stuff is a smarter move for me. Helping level GBs
I do not see any point for me to have(at this time in my game) mountains of Coins. I do know I will need mountains of Coins in late Eras.. just not right now. an Coins add up fast...
Turning the Coins into useful stuff is a smarter move for me. Helping level GBs
Darkest.Knight
Well-Known Member
Put up SMB after I finished up story questline and started spending gold on fps, I've been buying 100+/day for about 9 mo. and have bought 32000. After purchasing 32000 the cost is 1.6M/fps, I should be able to buy quite a few more since I'm cranking out about 180M gold/day.
Sharmon the Impaler
Well-Known Member
I have 2.1 billion coins and just the thought of buying FP with them makes my clicking finger hurt. I will wait until they (if) allow bulk purchases.
Sharmon the Impaler
Well-Known Member
180M coins per day ? I get 17.4 million per day and thought I was getting a lot , that is 67.5 billion coins per year.
DreadfulCadillac
Well-Known Member
When I get 1B coins, i'll be sitting down and doing 2K Rq's multiple days in a row. Free goods for Clicks
(Insert Money Eyes Emoji Here)
(Insert Money Eyes Emoji Here)
Wwwoodchuck
Active Member
I have been playing for 588 days. I have only purchased FP when asked to for a Quest, only event quests I believe. All except for Forge Bowl…. Whatever year it was when I started, I have complete every questline for every event. My next FP costs 14,000 coins. With the coins I have accumulated, I would be able to purchase 14,731 FP. HaHa!! (5.63G Coins) And no. I do not plan to start buying them just to use coins. I thought it would be interesting to see how much they would eventually cost just fulfilling Quest requirements.
Ebeondi Asi
Well-Known Member
The problem is converting them. If you never do it, then the day(s) you want to, your finger is going to wither in the attempt.
I convert Coins to Forge Points every single day. I used to keep a base of 20 million, minimum, now I keep a base of 100 million. I plan soon (after I finish getting St. Mark's Basilica to level 80) to keep a base total of one billion Coins. and constantly convert the rest into Forge Points. (the one billion only because I plan soon to enter Arctic Era, and the need for Coins to do Research does increase as the Eras increase)
My current cost is around 640,000 Coins per FP. I generally get 40 to 60 million Coins a day currently. I see zero problem having a future Coin to FP cost of a million plus.
THe reason to do this exchange is those coins sitting there do nothing for you. The converted to Forge Points do plenty. Leveling up GBs is a much better strategy as investment than hoarding several billion sitting doing nothing.
I convert Coins to Forge Points every single day. I used to keep a base of 20 million, minimum, now I keep a base of 100 million. I plan soon (after I finish getting St. Mark's Basilica to level 80) to keep a base total of one billion Coins. and constantly convert the rest into Forge Points. (the one billion only because I plan soon to enter Arctic Era, and the need for Coins to do Research does increase as the Eras increase)
My current cost is around 640,000 Coins per FP. I generally get 40 to 60 million Coins a day currently. I see zero problem having a future Coin to FP cost of a million plus.
THe reason to do this exchange is those coins sitting there do nothing for you. The converted to Forge Points do plenty. Leveling up GBs is a much better strategy as investment than hoarding several billion sitting doing nothing.
Darkest.Knight
Well-Known Member
At the end of the questline gold is almost useless, if u don't spend it what good is it? I save enough to cover anything that comes up including the extra new era costs; 1G is more than enough. So far 1.6M/fps isn't a problem and I'll keep buying 100+fps/day for awhile.
Mark-084
New Member
That would be nice but I am certain that your idea runs counter to their business plan. To a business revenue is "life blood!"
Ebeondi Asi
Well-Known Member
An update I now am in Arctic, have the one billion coins saved and more, plus my cost per FP is edging to 800,000 Coins per FP. With a level 80 St Marks in my cities I generally create an extra 60 plus Forge points a day added from Coins.
Lord Pest
Well-Known Member
when you get to OF there is a buy 5 fp recurring quest. In VF there is a buy 15 fp recurring quest.
Karen Isaacsdottir
Active Member
What do you have that autocollects coins? Asking as a new player...
Xenosaur
Well-Known Member
I do love math. For those of you that can watch this unfold, please do. It's kinda cool.
Let's make the problem simple. I have 1005 dollars. I can buy gems starting @ 2 dollar, and they go up .50 each time I buy a new one. Very similar to the FP for coins model used in FoE.
Here's your variables:
Y = bank of dollars (1005)
G = cost of the first gem (2)
X= Cost of each additional gem (.5)
N = how many gems can you buy?
You want to know how many gems you can buy, so the equation for that is expanded to look like this:
Y = G + (G + X), + (G + 2X) + ... + (G + NX)
If you rearrange the terms, you get this:
Y = (N+1) G + (1+2+3+...+N) X
As it turns out, 1+2+3+...+N = (N² + N)X/2
So ... the equation to solve for Y is:
Y = (N+1)G + (N² + N)X/2
If you plug in the values of Y = 1005, G = 2 and X=.5 ... you'll see N = 59.
Or more simply perhaps, plug in N = 59, G = 2 and X = .5 and you'll get 1005 for Y.
The equation is quadratic, in the variable N. You could simplify the right hand side if you see that it looks like a 2nd degree polynomial in the variable N of the form a + bn + cN².
Now.. this solves (at the moment), for Y.
To make it solve for N (how many gems you can get) in terms of Y, G, X - we'll have to take the quadratic equation, and "complete the square" in the variable N.
That's for another time..
Let's make the problem simple. I have 1005 dollars. I can buy gems starting @ 2 dollar, and they go up .50 each time I buy a new one. Very similar to the FP for coins model used in FoE.
Here's your variables:
Y = bank of dollars (1005)
G = cost of the first gem (2)
X= Cost of each additional gem (.5)
N = how many gems can you buy?
You want to know how many gems you can buy, so the equation for that is expanded to look like this:
Y = G + (G + X), + (G + 2X) + ... + (G + NX)
If you rearrange the terms, you get this:
Y = (N+1) G + (1+2+3+...+N) X
As it turns out, 1+2+3+...+N = (N² + N)X/2
So ... the equation to solve for Y is:
Y = (N+1)G + (N² + N)X/2
If you plug in the values of Y = 1005, G = 2 and X=.5 ... you'll see N = 59.
Or more simply perhaps, plug in N = 59, G = 2 and X = .5 and you'll get 1005 for Y.
The equation is quadratic, in the variable N. You could simplify the right hand side if you see that it looks like a 2nd degree polynomial in the variable N of the form a + bn + cN².
Now.. this solves (at the moment), for Y.
To make it solve for N (how many gems you can get) in terms of Y, G, X - we'll have to take the quadratic equation, and "complete the square" in the variable N.
That's for another time..